1x^2-20x-6=0

Solution for 1x^2-20x-6=0 equation:

1x^2-20x-6=0

We add all the numbers together, and all the variables

x^2-20x-6=0

a = 1; b = -20; c = -6;
Δ = b2-4ac
Δ = -202-4·1·(-6)
Δ = 424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{424}=\sqrt{4*106}=\sqrt{4}*\sqrt{106}=2\sqrt{106}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{106}}{2*1}=\frac{20-2\sqrt{106}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{106}}{2*1}=\frac{20+2\sqrt{106}}{2}
$